Given, $R_{1} = 1\Omega\ \ \ C_{1} = 2\mu F$ $R_{2} = 2\Omega\ \ \ C_{2} = 4\mu F$ [image:1_image83.emf] The time constant (in $\mu\ s$) for the circuits, I, II, III, are respectively

Question

Dr. Abubacker · Accepted Answer

(d) $	au_{1} = RC\left( \frac{1 	imes 2}{1 + 2} ight) 	imes \left( \frac{2 	imes 4}{2 + 4} ight) = \frac{2}{3} 	imes \frac{8}{6} = 8/9\ \mu\ s$
$	au_{2} = RC = (1 + 2)(2 + 4) = 3 	imes 6 = 18\ \mu\ s$
$	au_{3} = \left( \frac{1 	imes 2}{1 + 2} ight)(2 + 4) = \frac{2}{3} 	imes 6 = 4\ \mu\ s$

Q. Given, $R_{1} = 1\Omega\ \ \ C_{1} = 2\mu F$ $R_{2} = 2\Omega\ \ \ C_{2} = 4\mu F$

The time constant (in $\mu\ s$) for the circuits, I, II, III, are respectively

Explanation

Reviewed by Dr. Abubacker

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Q. Given, $R_{1} = 1\Omega\ \ \ C_{1} = 2\mu F$ $R_{2} = 2\Omega\ \ \ C_{2} = 4\mu F$ The time constant (in $\mu\ s$) for the circuits, I, II, III, are respectively

Explanation

Reviewed by Dr. Abubacker

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Q. Given, $R_{1} = 1\Omega\ \ \ C_{1} = 2\mu F$ $R_{2} = 2\Omega\ \ \ C_{2} = 4\mu F$

The time constant (in $\mu\ s$) for the circuits, I, II, III, are respectively