Q. A capacitor is charged to $200\ volt$ it has $0.1\ coulomb$ charge. When it is discharged, energy will be
A) $1\ J$
B) $4\ J$
C) $10\ J$
D) $20\ J$
Explanation
(c) Given $\Rightarrow V = 200\ volt,\ Q = 0.1\ C$
As energy $U = \frac{QV}{2},U = \frac{0.1 \times 200}{2} = 10\ Joule$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.