Q.
Consider an electric field $\overrightarrow{E} = E_{0}\widehat{x},$ where $E_{0}$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is
A) $2E_{0}a^{2}$
B) $\sqrt{2}E_{0}a^{2}$
C) $E_{0}a^{2}$
D) $\frac{E_{0}a^{2}}{\sqrt{2}}$
Explanation
(c) [image:1_image294.png]
Flux $= \lbrack E_{0}\cos 45^{o}\rbrack \times area$
$= \frac{E_{0}}{\sqrt{2}} \times a \times \sqrt{2}a = E_{0}a^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.