An electric dipole of moment p is placed at the origin along the $x$-axis. The electric field at a point P, whose position vector makes an angle $ heta$ with the $x$-axis, will make an angle With the $x$-axis, where $tan\ \alpha = \frac{1}{2}tan heta.$ [image:1_image87.emf]

Question

An electric dipole of moment p is placed at the origin along the $x$-axis. The electric field at a point P, whose position vector makes an angle $	heta$ with the $x$-axis, will make an angle With the $x$-axis, where $tan\ \alpha = \frac{1}{2}tan	heta.$ [image:1_image87.emf]

Dr. Abubacker · Accepted Answer

(b) On producing the rays backwards, we get $\angle PDX = (	heta + \alpha)$ is required angle.
[image:1_image295.emf]

Q. An electric dipole of moment p is placed at the origin along the $x$-axis. The electric field at a point P, whose position vector makes an angle $\theta$ with the $x$-axis, will make an angle With the $x$-axis, where $tan\ \alpha = \frac{1}{2}tan\theta.$

Explanation

Reviewed by Dr. Abubacker

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