Q. A thin spherical conducting shell of radius $R$ has a charge $q.$ Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $p$ a distance $R/2$ from the centre of the shell is
A) $\frac{(q + Q)}{4\pi\varepsilon_{0}}\frac{2}{R}$
B) $\frac{2Q}{4\pi\varepsilon_{0}R}$
C) $\frac{2Q}{4\pi\varepsilon_{0}R} - \frac{2q}{4\pi\varepsilon_{0}R}$
D) $\frac{2Q}{4\pi\varepsilon_{0}R} + \frac{2q}{4\pi\varepsilon_{0}R}$
Explanation
(d) Electric potential at $P$
[image:1_image296.emf]
$V = \frac{k.Q}{R/2} + \frac{k.q}{R}$
$= \frac{2Q}{4\pi\varepsilon_{0}R} + \frac{q}{4\pi\varepsilon_{0}R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.