Q. Electric field strength due to a point charge of $5\ \mu C$ at a distance of $80\ cm$ from the charge is
A) $8 \times 10^{4}N/C$
B) $7 \times 10^{4}N/C$
C) $5 \times 10^{4}N/C$
D) $4 \times 10^{4}N/C$
Explanation
(b) $E = 9 \times 10^{9}.\frac{Q}{r^{2}} = 9 \times 10^{9} \times \frac{5 \times 10^{- 6}}{(0.8)^{2}} = 7 \times 10^{4}N/C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.