Q. A parallel plate air capacitor has a capacitance of $100\mu\mu F.$ The plates are at a distance $d$ apart. If a slab of thickness $t(t \leq d)$ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be
A) $50\ \mu\mu F$
B) $100\ \mu\mu F$
C) $200\ \mu\mu F$
D) $500\ \mu\mu F$
Explanation
(c) Capacitance will increase but not 5 times [Because dielectric is not filled completely]. Hence new capacitance may be $200\ \mu\mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.