Q. Two charges of equal magnitudes and at a distance $r$ exert a force $F$ on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is
A) $F/8$
B) $F/4$
C) $4\ F$
D) $F/16$
Explanation
(d) $F = k.\frac{Q^{2}}{r^{2}}.$ If $Q$ is halved, $r$ is doubled then $F \rightarrow \frac{1}{16}$ times
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.