Q. A capacitor of capacitance $6\mu F$ is charged upto $100\ volt.$ The energy stored in the capacitor is
A) $0.6\ Joule$
B) $0.06\ Joule$
C) $0.03\ Joule$
D) $0.3\ Joule$
Explanation
(c) $U = \frac{1}{2}CV^{2} = \frac{1}{2} \times 6 \times 10^{- 6}(100)^{2} = 0.03J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.