Q. Two identical capacitors are joined in parallel, charged to a potential $V$ and then separated and then connected in series $i.e.$ the positive plate of one is connected to negative of the other
A) The charges on the free plates connected together are destroyed
B) The charges on the free plates are enhanced
C) The energy stored in the system increases
D) The potential difference in the free plates becomes $2V$
Explanation
(d) $Q_{1} = CV$ and $Q_{2} = CV$
Applying charge conservation $CV_{1} + CV_{2} = Q_{1} + Q_{2}$
$CV_{1} + CV_{2} = 2CV \Rightarrow V_{1} + V_{2} = 2V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.