The electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 20 Vm. The flux over a concentric sphere of radius 20 cm will be

Question

Dr. Abubacker · Accepted Answer

(a) According to Gauss’s law, electric flux is
$\phi_{E} = \oint_{}^{}{\ _{s}\mathbf{E.ds} = \frac{1}{\varepsilon_{0}}(q)\ }$
$ie$, the flux linked with a closed body is independent of the shape and size of the surface. So electric flux remain constant.
Hence, $\phi_{E} = 20Vm$

Q. The electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 20 Vm. The flux over a concentric sphere of radius 20 cm will be

Explanation

Reviewed by Dr. Abubacker

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