Q. A body has $- 80\ micro\ coulomb$ of charge. Number of additional electrons in it will be
A) $8 \times 10^{- 5}$
B) $80 \times 10^{- 17}$
C) $5 \times 10^{14}$
D) $1.28 \times 10^{- 17}$
Explanation
(c) By $Q = Ne$ or $N = \frac{Q}{e}\therefore N = \frac{80 \times 10^{- 6}}{1.6 \times 10^{- 19}} = 5 \times 10^{14}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.