Q. Two charges placed in air repel each other by a force of $10^{- 4}N.$ When oil is introduced between the charges, the force becomes $2.5 \times 10^{- 5}N.$ The dielectric constant of oil is
A) 2.5
B) 0.25
C) 2.0
D) 4.0
Explanation
(d) By using $K = \frac{F_{a}}{F_{m}} \Rightarrow K = \frac{10^{- 4}}{2.5 \times 10^{- 5}} = 4$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.