Q. A solid spherical conductor of radius $R$ has a spherical cavity of radius $a(a < R)$ at its centre. A charge $+ Q$ is kept at the center. The charge at the inner surface, outer and at a position $r(a < r < R)$ are respectively
A) $+ Q, - Q,0$
B) $- Q, + Q,0$
C) $0, - Q,0$
D) $+ Q,0,0$
Explanation
(b) The charge at the inner surface, outer surface and inside the conductor at $P = ( - Q, + Q,0)$ as shown in the figure
[image:1_image304.emf]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.