Q. Two condensers of capacities $1\mu F$ and $2\mu F$ are connected in series and the system is charged to $120\ volts.$ Then the P.D. on $1\mu F$ capacitor (in volts) will be
A) 40
B) 60
C) 80
D) 120
Explanation
(c) Charges developed are same so $C_{1}V_{1} = C_{2}V_{2} \Rightarrow \frac{V_{1}}{V_{2}} = 2$
$V_{1} + V_{2} = 120 \Rightarrow V_{1} = 80\ volts$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.