Q. Two charges is equal to $2\mu C$ are $0.5m$ apart. If both of them exist inside vacuum, then the force between them is
A) $1.89\ N$
B) $2.44\ N$
C) $0.144\ N$
D) $3.144\ N$
Explanation
(c) By using $F = 9 \times 10^{9}.\ \frac{Q^{2}}{r^{2}}$
$\Rightarrow F = 9 \times 10^{9\ .}\ \frac{\left( 2 \times 10^{- 6} \right)^{2}}{(0.5)^{2}} = 0.144\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.