Q. A capacitor is used to store $24\ watt$ hour of energy at 1200 $volt.$ What should be the capacitance of the capacitor
A) $120\ mF$
B) $120\ \mu F$
C) $24\ \mu F$
D) $24\ mF$
Explanation
(a) $U = \frac{1}{2}CV^{2}$ so $24 \times 60 \times 60 = \frac{1}{2}C(1200)^{2} \Rightarrow C = 120\ mF$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.