Q.
A solid conducting sphere of radius $a$ has a net positive charge $2Q$. A conducting spherical shell of inner radius $b$ and outer radius $c$ is concentric with the solid sphere and has a net charge $- Q.$ The surface charge density on the inner and outer surfaces of the spherical shell will be
A) $- \frac{2Q}{4\pi b^{2}},\frac{Q}{4\pi c^{2}}$
B) $- \frac{Q}{4\pi b^{2}},\frac{Q}{4\pi c^{2}}$
C) $0,\frac{Q}{4\pi c^{2}}$
D) None of the above
Explanation
(a) Surface charge density $(\sigma) = \ \frac{Charge}{surface\ area}$
[image:1_image308.emf]
So $\sigma_{inner} = \frac{- 2Q}{4\pi b^{2}}$
And $\sigma_{Outer} = \frac{Q}{4\pi c^{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.