Q. Three capacitors of capacitance $3\mu F,\ 10\mu F$ and $15\mu F$ are connected in series to a voltage source of $100V.$ The charge on $15\mu F$ is
A) $50\ \mu C$
B) $100\ \mu C$
C) $200\ \mu C$
D) $280\ \mu C$
Explanation
(c) $\frac{1}{C_{eq}} = \frac{1}{3} + \frac{1}{10} + \frac{1}{15} \Rightarrow C_{eq} = 2\mu F$
Charge on each capacitor
$Q = C_{eq} \times V \Rightarrow 2 \times 100 = 200\mu C$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.