The capacity of a parallel plate condenser is $10\mu F$ without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in $\mu F$ is

Question

Dr. Abubacker · Accepted Answer

(d) $C = \frac{A\varepsilon_{0}}{d} = 10\mu F$
$C_{1} = \frac{A\varepsilon_{0}}{d - t + \frac{t}{k}} = \frac{A\varepsilon_{0}}{d - \frac{d}{2} + \frac{d}{2k}} = \frac{A\varepsilon_{0}}{\frac{d}{2}\left( 1 + \frac{1}{2} ight)} = \frac{4}{3}.\frac{A\varepsilon_{0}}{d}$
$	herefore C_{1} = \frac{4}{3} 	imes 10 = 13.33\mu F$

Q. The capacity of a parallel plate condenser is $10\mu F$ without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in $\mu F$ is

Explanation

Reviewed by Dr. Abubacker

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