Q. A ring of radius $r$ carries a charge $Q$ uniformly distributed over its length. A charge $q$ is placed at its centre will experience a force equal to
A) $\frac{qQ}{4\pi\varepsilon_{0}r^{2}}$
B) $\frac{qQ}{8\pi\varepsilon_{0}r^{3}}$
C) Zero
D) None of these
Explanation
(c) The electric field (E) at the centre of circular charged ring of radius $R$ is zero
$\therefore$ Force $= qE =$ Zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.