Q.
The electric flux for Gaussian surface A that enclose the charged particles in free space is $\left( given\ q_{1} = - 14nC,\ q_{2} = 78.85nC,q_{3} = - 56nC \right)$
A) $10^{3}Nm^{2}C^{- 1}$
B) $10^{3}CN^{- 1}m^{- 2}$
C) $6.32 \times 10^{3}Nm^{2}C^{- 1}$
D) $6.32 \times 10^{3}CN^{- 1}m^{- 1}$
Explanation
(a) Electric flux =$\frac{q}{\varepsilon_{0}}$
$= \frac{( - 14 + 78.85 - 56) \times 10^{9}}{8.85 \times 10^{- 12}}$
$= \frac{8.85 \times 10^{- 9}}{8.85 \times 10^{- 12}} = 1000\ Nm^{2}C^{- 1}\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.