Q. When two identical capacitors are in series have $3\mu F$ capacitance and when parallel $12\mu F.$ What is the capacitance of each
A) $6\mu\ F$
B) $3\mu\ F$
C) $12\mu\ F$
D) $9\mu\ F$
Explanation
(a) In series $C^{'} = C/n\ i.e.\ C = nC^{'} = 2 \times 3 = 6\ \mu F$
In parallel $C^{'} = nC\ i.e.\ C = \frac{C^{'}}{n} = \frac{12}{2} = 6\ \mu F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.