Q. If a charged spherical conductor of radius $10cm$ has potential $V$ at a point distant $5\ cm$ from its centre, then the potential at a point distant $15\ cm$ from the centre will be
A) $\frac{1}{3}V$
B) $\frac{2}{3}V$
C) $\frac{3}{2}V$
D) $3V$
Explanation
(b) Potential inside the sphere will be same as that on its surface $i.e.\ V = V_{surface} = \frac{q}{10}stat\ volt,\ V_{out} = \frac{q}{15}stat\ volt$
$\therefore\frac{V_{out}}{V} = \frac{2}{3} \Rightarrow V_{out} = \frac{2}{3}V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.