Q. In a hollow spherical shell potential $(V)$ changes with respect to distance $(r)$ from centre
A)
B)
C)
D)
Explanation
(b) $V_{inside} = \frac{Q}{4\pi\varepsilon_{0}R}$ for $r \leq R$ …(i)
And $V_{out} = \frac{Q}{4\pi\varepsilon_{0}r}$ for $r \geq R$ …(ii)
$i.e.$ potential inside the hollow spherical shell is constant and outside varies according to $V \propto \frac{1}{r}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.