Q. The electric field that can balance a deuteron of mass $3.2 \times 10^{- 27\ }kg$ is
A) $19.6 \times 10^{- 10\ }NC^{- 1}$
B) $19.6 \times 10^{- 8\ }NC^{- 1}$
C) $19.6 \times 10^{10\ }NC^{- 1}$
D) $19.6 \times 10^{8\ }NC^{- 1}$
Explanation
(b) $E = \frac{f}{q} = \frac{mg}{q} = \frac{3.2 \times 10^{- 27} \times 9.8}{1.6 \times 10^{- 19}}\ $
$= 19.6 \times 10^{- 8}\ NC^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.