A network of four capacitors of capacity equal to $C_{1} = C,\ C_{2} = 2C,\ C_{3} = 3C$ and $C_{4} = 4C$ are conducted in a battery as shown in the figure. The ratio of the charges on $C_{2}$ and $C_{4}$ is [image:1_image106.emf]

Question

Dr. Abubacker · Accepted Answer

(b) The given circuit can be redrawn as follow
[image:1_image316.emf]
$C_{eq} = \frac{C_{1}C_{2}C_{3}}{C_{1}C_{2} + C_{2}C_{3} + C_{3}C_{1}} = \frac{6C}{11}$
$\frac{Q_{A}}{Q_{B}} = \frac{C_{A}}{C_{B}} = \frac{6C/11}{4C} = \frac{3}{22}$

Q. A network of four capacitors of capacity equal to $C_{1} = C,\ C_{2} = 2C,\ C_{3} = 3C$ and $C_{4} = 4C$ are conducted in a battery as shown in the figure. The ratio of the charges on $C_{2}$ and $C_{4}$ is

Explanation

Reviewed by Dr. Abubacker

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