Q.
A gang capacitor is formed by interlocking a number of plates as shown in figure. The distance between the consecutive plates is $0.885\ cm$ and the overlapping area of the plate is $5\ cm^{2}.$ The capacity of the unit is
A) $1.0$
B) $4\ pF$
C) $6.36\ pF$
D) $12.72\ pF$
Explanation
(b) There are 8 capacitor in this gang and all of them are in parallel combination
$C_{eq} = 8.C = \frac{8\varepsilon_{0}A}{d}$
$= \frac{8 \times 8.85 \times 10^{- 12} \times 5 \times 10^{- 4}}{0.885 \times 10^{- 2}} = 4 \times 10^{- 12} = 4\ pF$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.