Q. A charge $q$ is placed at the centre of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is
A) Zero
B) $\frac{q}{\varepsilon_{0}}$
C) $\frac{q}{2\varepsilon_{0}}$
D) $\frac{2q}{\varepsilon_{0}}$
Explanation
(c) To apply Gauss’s theorem it is essential that charge should be placed inside a closed surface. So imagine another similar cylindrical vessel above it as shown in figure (dotted)
[image:1_image326.png]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.