Q.
What is the equivalent capacitance between $A$ and $B$ in the given figure (all are in farad)
A) $\frac{13}{18}F$
B) $\frac{48}{13}F$
C) $\frac{1}{31}F$
D) $\frac{240}{71}F$
Explanation
(d) The given circuit can be simplified as follows
[image:1_image327.emf]
Hence equivalent capacitance between $A$ and $B$
$\frac{1}{C_{AB}} = \frac{1}{12} + \frac{1}{20/3} + \frac{1}{16} \Rightarrow C_{AB} = \frac{240}{71}F$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.