Q.
Plates of area $A$ are arranged as shown. The distance between each plate is $d,$ the net capacitance is
A) $\frac{\varepsilon_{0}A}{d}$
B) $\frac{{7\varepsilon}_{0}A}{d}$
C) $\frac{{6\varepsilon}_{0}A}{d}$
D) $\frac{{5\varepsilon}_{0}A}{d}$
Explanation
The correct answer is Option A: $\frac{\varepsilon_{0}A}{d}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.