Explanation

(d) The electric field intensity at a point lying outside the sphere (non-conducting) is
$E = \frac{1}{4\pi\varepsilon_{0}}\frac{q}{r^{2}}$
Where $r$ is the distance of that point from centre of sphere.
$E \propto \frac{1}{r^{2}}\ \ \ \ \ \ \ldots.(i)$
The electric field intensity at surface of sphere
$E = \frac{q}{4\pi\varepsilon_{0}R^{2}}$
Or
$E \propto \frac{1}{R^{2}}\ \ \ \ \ \ \ \ldots.(ii)$
R, being the radius of sphere.
The electric field intensity at a point lying inside the sphere is
$E = \frac{qr}{4\pi\varepsilon_{0}R^{3}}$
Or $E \propto r\ \ \ldots\ldots.(iii)$
Also at the centre of sphere r=0.
Hence,
The graphical distribution is shown below
[image:1_image330.emf]