Q. Two electric dipoles of moment $P$ and $64\ P$ are placed in opposite direction on a line at a distance of $25\ cm.$ The electric field will be zero at point between the dipoles whose distance from the dipole of moment $P$ is

A) $5\ cm$
B) $\frac{25}{9}\ cm$
C) $10\ cm$
D) $\frac{4}{13}\ cm$
Explanation

(a) Suppose neutral point $N$ lies at a distance $x$ from dipole of moment $p$ or at a distance $(25$-$x)$ from dipole of 64 $p$
At $N$ |E.F. due to dipole | =|E.F. due to dipole |
$\Rightarrow \frac{1}{4\pi\varepsilon_{0}}.\frac{2p}{x^{3}} = \frac{1}{4\pi\varepsilon_{0}}.\frac{2(64p)}{(25 - x)^{3}}$
$\Rightarrow \frac{1}{x^{3}} = \frac{64}{(25 - x)^{3}} \Rightarrow x = 5\ cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.