Charges $4Q,q$ and $Q$ and placed along $x -$axis at positions $x = 0,\ x = l/2$ and $x = l,$ reapectively. Find the value of $q$ so that force on charge $Q$ is zero

Question

Dr. Abubacker · Accepted Answer

(d) The total force on $Q$
$\frac{Qq}{4\pi\varepsilon_{0}\left( \frac{l}{2} \right)^{2}} + \frac{4Q^{2}}{4\pi\varepsilon_{0}l^{2}} = 0$
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$\frac{Qq}{4\pi\varepsilon_{0}\left( \frac{l}{2} \right)^{2}} = - \frac{4Q^{2}}{4\pi\varepsilon_{0}l^{2}} \Rightarrow q = - Q$

Q. Charges $4Q,q$ and $Q$ and placed along $x -$axis at positions $x = 0,\ x = l/2$ and $x = l,$ reapectively. Find the value of $q$ so that force on charge $Q$ is zero

Explanation

Reviewed by Dr. Abubacker

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