Q. A parallel plate capacitor has an electric field of $10^{5}V/m$ between the plates. If the charge on the capacitor plate is $1\mu\ C,$ the force on each capacitor plate is
A) $0.5\ N$
B) $0.05\ N$
C) $0.005\ N$
D) None of these
Explanation
(b) $F = \frac{CV^{2}}{2d} = \frac{Q \times E}{2} = \frac{10^{- 6} \times 10^{5}}{2} = 0.05N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.