Electric charge of $1\mu C,\ - 1\mu C$ and $2\mu C$ are placed in air at the corners $A,\ B$ and $C$ respectively of an equilateral triangle $ABC$ having length of each side $10\ cm.$ The resultant force on charge at $C$ is

Question

Dr. Abubacker · Accepted Answer

(b) $F_{A} =$ Force on $C$ due to charge placed at $A$
$= \ 9 	imes 10^{9} 	imes \frac{10^{- 6} 	imes 2 	imes 10^{- 6}}{\left( 10 	imes 10^{- 2} ight)^{2}\ \ } = 1.8N$
$F_{B} =$ Force on $C$ due to charge placed at $B$
$= \ 9 	imes 10^{9} 	imes \frac{10^{- 6} 	imes 2 	imes 10^{- 6}}{(0.1)^{2}\ \ } = 1.8N$
Net force on $C$
$F_{net} = \sqrt{\left( F_{A} ight)^{2} + \left( F_{B} ight)^{2} + 2F_{A}\ F_{B}\ \cos{120{^\circ}}} = 1.8N$

Q. Electric charge of $1\mu C,\ - 1\mu C$ and $2\mu C$ are placed in air at the corners $A,\ B$ and $C$ respectively of an equilateral triangle $ABC$ having length of each side $10\ cm.$ The resultant force on charge at $C$ is

Explanation

Reviewed by Dr. Abubacker

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