Q. A square surface of side $L\ meteres$ is in the plane of the paper. A uniform electric field $\overrightarrow{E}\ (volt/m),$ also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux is SI units associated with the surface is

A) Zero
B) $EL^{2}$
C) $EL^{2}/(2\varepsilon_{0})$
D) $EL^{2}/2$
Explanation

(a) Electric flux, $\phi_{E} = \int_{}^{}{\overrightarrow{E}.\overrightarrow{dS}}$
$= \int_{}^{}{EdS\cos\theta = \int_{}^{}{EdS\cos{90{^\circ}} = 0}}$
The lines are parallel to the surface

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.