Q. The charge $q$ is projected into a uniform electric field E, work done when it moves a distance $Y$ is
A) $qEY$
B) $\frac{qY}{E}$
C) $\frac{qE}{Y}$
D) $\frac{Y}{qE}$
Explanation
(a) Force on a charge $q$ in a uniform electric field $E$ is $F = qE$
Work done = force $\times$ distance = $qEY$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.