Q. Four capacitors of each of capacity $3\mu F$ are connected as shown in the adjoining figure. The ratio of equivalent capacitance between $A$ and $B$ and between $A$ and $C$ will be

A) 4 : 3
B) 3 : 4
C) 2 : 3
D) 3 : 2
Explanation

(a) $C_{AB} = 3 + \frac{3}{3} = 4\mu F\ ,\ C_{AC} = \frac{3}{2} + \frac{3}{2} = 3\mu F$
$\therefore C_{AB}:C_{AC} = 4\ :3$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.