An electron falls through a small distance in a uniform electric field of magnitude $2 imes 10^{4}NC^{- 1}.$ The direction of the field is reversed keeping the magnitude unchanged and a proton falls through the same distance. The time of fall will be

Question

An electron falls through a small distance in a uniform electric field of magnitude $2 	imes 10^{4}NC^{- 1}.$ The direction of the field is reversed keeping the magnitude unchanged and a proton falls through the same distance. The time of fall will be

Dr. Abubacker · Accepted Answer

(c) The time required to fall through distance $d$ is
$d = \frac{1}{2}\left( \frac{qE}{m} \right)t^{2}$ or $t = \sqrt{\frac{2dm}{qE}}$
$Since\ t^{2} \propto m,$ a proton takes more time

Q. An electron falls through a small distance in a uniform electric field of magnitude $2 \times 10^{4}NC^{- 1}.$ The direction of the field is reversed keeping the magnitude unchanged and a proton falls through the same distance. The time of fall will be

Explanation

Reviewed by Dr. Abubacker

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