Q. A particle of $'m'$ and charge $'q'$ is accelerated through a potential difference of $V\ volt,$ its energy will be
A) $qV$
B) $mqV$
C) $\left( \frac{q}{m} \right)V$
D) $\frac{q}{mV}$
Explanation
(a) $KE = qV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.