Q. In the given figure two tiny conducting balls of identical mass $m$ and identical charge $q$ hang from non-conducting threads of equal length $L.$ Assume that $\theta$ is so small that $\tan\theta \approx \sin\theta,$ then for equilibrium $x$ is equal to

A) $\left( \frac{q^{2}L}{2\pi\varepsilon_{0}mg} \right)^{\frac{1}{3}}$
B) $\left( \frac{qL^{2}}{2\pi\varepsilon_{0}mg} \right)^{\frac{1}{3}}$
C) $\left( \frac{q^{2}L^{2}}{4\pi\varepsilon_{0}mg} \right)^{\frac{1}{3}}$
D) $\left( \frac{q^{2}L}{4\pi\varepsilon_{0}mg} \right)^{\frac{1}{3}}$
Explanation

The correct answer is Option A: $\left( \frac{q^{2}L}{2\pi\varepsilon_{0}mg} \right)^{\frac{1}{3}}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.