(b) Due to induction net charges on outer surfaces of spheres are as shown
$\sigma = \frac{Q_{1}}{4\pi R^{2}} = \ \frac{Q_{1} + Q_{2}}{4\pi(2R)^{2}} = \ \frac{Q_{1} + Q_{2} + Q_{3}}{4\pi(3R)^{2}}$
$\Rightarrow Q_{1} = \frac{Q_{1} + Q_{2}}{4} = \ \frac{Q_{1} + Q_{2} + Q_{3}}{9}$
$\Rightarrow Q_{2} = 3Q_{1}$ and $Q_{3} = 5Q_{1}$
$\therefore Q_{1}:Q_{2}:Q_{3} = 1:3:5$