In a given network the equivalent capacitance between $A$ and $B$ is $\lbrack C_{1} = C_{4} = 1\mu F,C_{2} = C_{3} = 2\mu F\rbrack$ [image:1_image160.emf]

Question

Dr. Abubacker · Accepted Answer

(a) $C_{2}$ and $C_{3}$ are in series so equivalent capacitance
$= \frac{2 	imes 2}{2 + 2} = 1$
$\Rightarrow$ Now $1\mu F,1\mu F$ and $1\mu F$ are in parallel
$	herefore C_{eq} = 1 + 1 + 1 = 3\mu F$

Q. In a given network the equivalent capacitance between $A$ and $B$ is $\lbrack C_{1} = C_{4} = 1\mu F,C_{2} = C_{3} = 2\mu F\rbrack$

Explanation

Reviewed by Dr. Abubacker

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