Two charges of $4\ \mu C$ each are placed at the corners $A$ and $B$ of an equilateral triangle of side length $0.2\ m$ in air. The electric potential at $C$ is $\left\lbrack \frac{1}{4\pi\varepsilon_{0}} = 9 imes 10^{9}\frac{N - m^{2}}{C^{2}} ight brack$

Question

Two charges of $4\ \mu C$ each are placed at the corners $A$ and $B$ of an equilateral triangle of side length $0.2\ m$ in air. The electric potential at $C$ is $\left\lbrack \frac{1}{4\pi\varepsilon_{0}} = 9 	imes 10^{9}\frac{N - m^{2}}{C^{2}} ightbrack$

Dr. Abubacker · Accepted Answer

(c) Potential at $C = \left( 9 	imes 10^{9} 	imes \frac{4 	imes 10^{- 6}}{0.2} ight) 	imes 2 = 36 	imes 10^{4}\ V$

Q. Two charges of $4\ \mu C$ each are placed at the corners $A$ and $B$ of an equilateral triangle of side length $0.2\ m$ in air. The electric potential at $C$ is $\left\lbrack \frac{1}{4\pi\varepsilon_{0}} = 9 \times 10^{9}\frac{N - m^{2}}{C^{2}} \right\rbrack$

Explanation

Reviewed by Dr. Abubacker

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