Q.
In the circuit here, the steady state voltage across capacitor $C$ is a fraction of the battery e.m.f. The fraction is decided by
A) $R_{1}$ only
B) $R_{1}$ and $R_{2}$ only
C) $R_{1}$ and $R_{3}$ only
D) $R_{1},R_{2}$ and $R_{3}$
Explanation
(b) In steady state potential difference across capacitor
$V_{2} =$ potential difference across resistance $R_{2} = \left( \frac{R_{2}}{R_{1} + R_{2}} \right)V$
Hence $V_{2}$ depends upon $R_{2}$ and $R_{1}$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.