Q. There is a solid sphere of radius $'R'$ having uniformly distributed charge. What is the relation between electric field $'E'$ (inside the sphere) and radius of sphere $'R'$ is
A) $E \propto R^{- 2}$
B) $E \propto R^{- 1}$
C) $E \propto \frac{1}{R^{3}}$
D) $E \propto R^{2}$
Explanation
(c) $E = \frac{1}{4\pi\varepsilon_{0}}.\frac{Qr}{R^{3}} \Rightarrow E \propto \frac{1}{R^{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.