Q. Two plates are at potentials $- 10\ V$ and $+ 30\ V.$ If the separation between the plates be $2\ cm.$ The electric field between them is
A) $2000\ V/m$
B) $1000\ V/m$
C) $500\ V/m$
D) $3000\ V/m$
Explanation
(a) $E = \frac{V}{d} = \frac{30 - ( - 10)}{(2 \times 10^{- 2})} = 2000\ V/m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.