Q. A series combination of three capacitors of capacities $1\mu\ F,2\mu\ F$ and $8\mu\ F$ is connected to a battery of e.m.f. 13 $volt.$ The potential difference across the plates of $2\ \mu\ F$ capacitor will be
A) $1V$
B) $8V$
C) $4V$
D) $\frac{13}{3}V$
Explanation
(c) $\frac{1}{C_{eq}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{8} \Rightarrow C_{eq} = \frac{8}{13}\mu F$
Total charge $Q = C_{eq}V = \frac{8}{13} \times 13 = 8\mu C$
Potential difference across $2\mu F$ capacitor $= \frac{8}{2} = 4V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.