Q. Figure (a) shows two capacitors connected in series and joined to a battery. The graph in figure (b) shows the variation in potential as one moves from left to right on the branch containing the capacitors, if
A) $C_{1} > C_{2}$
B) $C_{1} = C_{2}$
C) $C_{1} < C_{2}$
D) The information is not sufficient to decide the relation between $C1$ and $C_{2}$
Explanation
(c) According to graph we can say that potential difference across the capacitor $C_{1}$ is more than that across $C_{2}.$ Since charge $Q$ is same $i.e.,\ Q = C_{1}V_{1} = C_{2}V_{2}$
$\Rightarrow \frac{C_{1}}{C_{2}} = \frac{V_{2}}{V_{1}} \Rightarrow C_{1} < C_{2}\ \ \ \ \ \ \left\lbrack V_{1} > V_{2} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.